2x(x+3)=2(x^2+3)

Solution for 2x(x+3)=2(x^2+3) equation:

Simplifying
2x(x + 3) = 2(x2 + 3)

Reorder the terms:
2x(3 + x) = 2(x2 + 3)
(3 * 2x + x * 2x) = 2(x2 + 3)
(6x + 2x2) = 2(x2 + 3)

Reorder the terms:
6x + 2x2 = 2(3 + x2)
6x + 2x2 = (3 * 2 + x2 * 2)
6x + 2x2 = (6 + 2x2)

Add '-2x2' to each side of the equation.
6x + 2x2 + -2x2 = 6 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6x + 0 = 6 + 2x2 + -2x2
6x = 6 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6x = 6 + 0
6x = 6

Solving
6x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = 1

Simplifying
x = 1